q=P.%26%2341%EF%BC%8C%26%2340%E6%B3%95%26%2341%E9%B2%81%E6%A0%BC%E7%BD%97%E5%B0%94%26%2340Rouquerol&searchType=standard&isFacet=true&view=standard&searchWay=author&rows=10&sortWay=score&sortOrder=desc&searchWay0=marc&logical0=AND
rows=10&searchWay0=marc&logical0=AND
P.)，(法)鲁格罗尔(Rouquerol